WebApr 25, 2024 · There are $\binom{10}{10}+\binom{10}{9}=1+10=11$ ways to get a string of length ten with strictly more than eight 1's. Subtracting this from $2^{10}=1024$, the total … WebAnswer is 2184. (b) Since it's a bit string of 14 digits and there can be only digits 0 or 1, we need to select 7 0s and the rest would be 7 1s, so the number of permutations would be equal to \frac {14!} { (14-7)!}=14\cdot13\cdot12\cdot...\cdot8=17297280 (14−7)!14! = 14⋅13⋅12⋅... ⋅8 = 17297280 . The answer is 17297280.

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WebThe number of bits (0's or 1's) in the string is the length of the string; the strings above have lengths 4, 1, 4, and 10 respectively. We also can ask how many of the bits are 1's. The number of 1's in a bit string is the weight of the string; the weights of the above strings are 2, 0, 4, and 5 respectively. 🔗 Bit Strings. Webn−2 positions, so that we have a n−2 such strings. If a string of length n ends with 00, then, whatever bits are at the first n − 2 positions, such a string already contains a pair of consecutive 0s, and we have 2n−2 such strings. Therefore, we obtain that a n = a n−1 +a n−2 +2 n−2. (b) a 0 = a 1 = 0 since a string of length less ... jeb fields memphis

How many bit strings of length 8 have an equal number of 0

WebJan 13, 2011 · How many bit strings of length 10 have? 1024 How many bit strings are there of length eight? Every bit can either be a 0 or 1. So to find the amount of bit strings of length... WebJan 13, 2011 · There are 120 bit strings of length 10 with exactly three 0s. Wiki User ∙ 2011-01-13 07:24:55 This answer is: Study guides Algebra 20 cards A polynomial of degree … jeb dunnuck the wine advocate