Or ax 1234h or 0ffh
WebTranscribed Image Text: Q2) if DS-3456H,SS-234AH, IP ADFCH Mov [2345H], 5675H Mov AX, 1234H ADD AX, [2345H] The final value of AX is A) 3579H b) 68A9H C) 3579D d) 1234H … Web教材习题集习 题 一1.1 试分别将下列二进制数真值用补码表示8位二进制数.101101011 201011100 300111111 4011110111.2. 试分别将下列补码表示的二进制数转换为相应的十进制数真值.111111110
Or ax 1234h or 0ffh
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WebFeb 4, 2024 · (2)将存储单元 3000h 和内容送至 4000h 单元。 (3)将累加器 aX 与寄存器 cx 中的内容对调. 答案: (1)mov aX, 1234H Mov ds, ax movAx, [3000H] mov [4000H], ax xchgax, cx 12.编程:将数据段中以 Bx 为偏移地址的连续 单元的内容颠倒过来。 WebDec 31, 2024 · This instruction does more or less the opposite of MOV AX, [BX]: It writes data to memory. This time, the data in the register BX is written to the memory specified by the registers DS and AX. Because on x86 systems the low byte of some data is stored in the first byte and the high byte is stored in the second byte, the value 1234h would be ...
WebApr 13, 2024 · 想预览更多内容,点击免费在线预览全文 WebDoc-9MXMRS;本文是“资格或认证考试”中“教师资格考试”的实用应用文的论文参考范文或相关资料文档。正文共16,068字,word格式文档。内容摘要:填空,位偏移量)和(SP)提供,单项选择题,判断题(你认为正确的,请在题末的括号内打“√”,错的打“×,简答题,位机,如何响应一个可屏蔽 ...
Web微机原理与接口技术期中考试题(带答案)_试卷_中考 Webmov ax,00FFh inc ax ; AX = 0100h mov ax,00FFh inc al ; AX = 0000h Show the value of the destination operand after each of the following instructions executes: .data myByte BYTE …
Web解答:(1)指令oR AX,1234H oR 0FFH 中的第一个oR 是指令系统中的“或”指令,而 第二个oR 是表达式中表示逻辑“或”关系的。(2)指令oR AX,1234H oR 0FFH 中的第一个 . 26 . oR …
WebIf AX-1234H and DX- 20FFH, list the sum and the contents of each flag register bit (C, S, and Z) after the ADD AX, DX instruction executes. 2. This problem has been solved! lingering appendicitisWebMar 26, 2024 · 1. @Linux The answer is FF00h: AL is incremented and wraps around from FFh to 00h, and AH is unchanged at FFh. Note that the "low", i.e. least-significant bits are written on the right. So for instance when AX = 1234h, you have AH = 12h and AL = 34h. … lingering around meaningWebApr 8, 2024 · MOV [1234H], AX means that the value of AX is copied to 1234 hexadecimal address in memory. So, please correct me if what I am saying is wrong, the [] operator functions as a pointer to, right? This being said, I can't understand the following instruction: MOV [EBX], AX why the use of the [ ]? lingering around the tableWebmov ax,7FFFh add ax,2 ; SF = 1 ; Carry flag example: mov al,0FFh add al,1 ; CF = 1, AL = 00 ; Overflow flag example: mov al,+127 add al,1 ; OF = 1 mov al,-128 sub al,1 ; OF = 1 exit main ENDP END main Programming Exercises 1. Indicate whether or not each of the following instructions is valid. a. add ax,bx b. add dx,bl lingering accessoriesWebNov 21, 2024 · AX=FFFFh CF=1(result is not 0) SF=1 ZF=0 PF=1 OF=0 Question 2: a) Suppose that AX and BX both contains +ive numbers, and ADD AX, BX is executed , show that there is carry into the MSB but no carry out of the MSB if and only if, signed overflow occurs. Solution: As we know signed overflow occurs if and if: There is a carry into the … hot tubs millsboro deWeb8. (5 points) Write a short sequence of instructions to store the contents of the CX register at theword memory location contained in CX. Thus if CX contains 1234h, the number 1234h will be stored at locations DS:1234h and DS:1235h in memory. mov bx,cx mov [bx],cx mov bx , cx mov [ bx ] , cx hot tubs monmouth county njWebThere are 8 different addressing modes in 8086 programming − Immediate addressing mode The addressing mode in which the data operand is a part of the instruction itself is known as immediate addressing mode. Example MOV CX, 4929 H, ADD AX, 2387 H, MOV AL, FFH Register addressing mode lingering around synonym